SSC/Stability/Yabushita75: Difference between revisions

From jetwiki
Jump to navigation Jump to search
No edit summary
 
(19 intermediate revisions by the same user not shown)
Line 24: Line 24:
&nbsp; &nbsp; &nbsp; at &nbsp; &nbsp; &nbsp; <math>\xi = 0</math>.
&nbsp; &nbsp; &nbsp; at &nbsp; &nbsp; &nbsp; <math>\xi = 0</math>.
</div>
</div>
As has been demonstrated in [[Appendix/Ramblings/PowerSeriesExpressions#IsothermalLaneEmden|our accompanying ''mathematics'' appendix]], a series expansion about the center of the isothermal configuration gives,
<table border="0" cellpadding="5" align="center">
<tr>
  <td align="right">
<math>\psi(\xi)
</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>~\frac{\xi^2}{6} - \frac{\xi^4}{120} + \frac{\xi^6}{1890} - \frac{61 \xi^8}{1,632,960} + \cdots \, .</math>
  </td>
</tr>
</table>


The solution, <math>\psi(\xi)</math>, extends to infinity, so the interface between the core and the envelope can be positioned anywhere within the range, <math>0 < \xi_i < \infty</math>.
The solution, <math>\psi(\xi)</math>, extends to infinity, so the interface between the core and the envelope can be positioned anywhere within the range, <math>0 < \xi_i < \infty</math>.
Line 30: Line 47:


<div align="center">
<div align="center">
<table border="0" cellpadding="3">
<table border="0" cellpadding="3" width="50%">
<tr>
<tr>
   <td align="center" colspan="3">
   <td align="center" colspan="4">
Specify:  <math>c_s^2</math> and <math>\rho_0 ~\Rightarrow</math>
Specify:  <math>c_s^2</math> and <math>\rho_0 ~\Rightarrow</math>
   </td>
   </td>
Line 47: Line 64:
<math>\biggl[ \frac{c_s^2}{4\pi G\rho_0} \biggr]^{1/2} \xi</math>
<math>\biggl[ \frac{c_s^2}{4\pi G\rho_0} \biggr]^{1/2} \xi</math>
   </td>
   </td>
  <td align="right">(2.2)</td>
</tr>
</tr>


Line 59: Line 77:
<math>\rho_0 e^{-\psi}</math>
<math>\rho_0 e^{-\psi}</math>
   </td>
   </td>
  <td align="right">(2.2)</td>
</tr>
</tr>


Line 71: Line 90:
<math>c_s^2 \rho_0 e^{-\psi}</math>
<math>c_s^2 \rho_0 e^{-\psi}</math>
   </td>
   </td>
  <td align="right">(2.1)</td>
</tr>
</tr>


Line 83: Line 103:
<math>\biggl[ \frac{c_s^6}{4\pi G^3\rho_0} \biggr]^{1/2} \biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)</math>
<math>\biggl[ \frac{c_s^6}{4\pi G^3\rho_0} \biggr]^{1/2} \biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)</math>
   </td>
   </td>
  <td align="right">(2.3)</td>
</tr>
<tr><td colspan="4" align="center">{{ Yabushita75 }}, &sect; 2, pp. 442-443</td></tr>
</table>
</div>
After adopting the substitute notation, <math>c_s^2 \rightarrow K_1</math> and <math>\rho_0 \rightarrow \lambda_c</math>, it is clear that these last four parameter-profile expressions are identical  to the ones that appear, respectively, as equations (2.2), (2.1) and (2.3) of {{ Yabushita75 }}.
===Step 5: Interface Conditions===
<div align="center">
<!-- BEGIN RIGHT BLOCK details -->
<table border="0" cellpadding="3">
<tr>
  <td align="right">
<math>\biggl( \frac{\rho_0}{\mu_c} \biggr) e^{-\psi_i}</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl( \frac{\rho_e}{\mu_e} \biggr) \theta^{n_e}_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl( \frac{\rho_e}{\mu_e} \biggr) \theta^{3 / 2}_i</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>c_s^2 \rho_0 e^{-\psi_i}</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>K_e \rho_e^{1+1/n_e} \theta^{n_e + 1}_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>K_e \rho_e^{5 / 3} \theta^{5 / 2}_i</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\biggl[ \frac{c_s^2}{4\pi G\rho_0} \biggr]^{1/2} \xi_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{(n_e + 1)K_e}{4\pi G} \biggr]^{1/2} \rho_e^{(1-n_e)/(2n_e)} \eta_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{(5 / 2)K_e}{4\pi G} \biggr]^{1/2} \rho_e^{(-1 / 6)} \eta_i</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\biggl[ \frac{c_s^6}{4\pi G^3\rho_0} \biggr]^{1/2} \biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{(n_e + 1)K_e}{4\pi G} \biggr]^{3/2} \rho_e^{(3-n_e)/(2n_e)} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_i</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{(5 / 2)K_e}{4\pi G} \biggr]^{3/2} \rho_e^{1 / 2} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_i</math>
  </td>
</tr>
</table>
<!-- END RIGHT BLOCK details -->
</div>
This means that,
<table border="0" align="center" cellpadding="8">
<tr>
  <td align="right"><math>\frac{\rho_e}{\rho_0}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>K_e
\biggl[\rho_0 \biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2} \biggr]^{5 / 3} \theta^{5 / 2}_i</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
c_s^2 \rho_0 e^{-\psi_i}
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\Rightarrow ~~~ \frac{K_e \rho_0^{2 / 3}}{c_s^2}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{-5 / 3}e^{+2\psi_i/3}
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\Rightarrow ~~~ \frac{c_s^2}{K_e}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl[
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 2} \rho_0e^{-\psi_i}
\biggr]^{2 / 3}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\frac{\eta_i }{\xi_i}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl[ \frac{c_s^2}{4\pi G\rho_0} \biggr]^{1/2} \biggl[ \frac{4\pi G}{(5 / 2)K_e} \biggr]^{1/2}
\biggl[ \rho_e \biggr]^{1 / 6}
</math>
  </td>
</tr>
<tr>
  <td align="right">&nbsp;</td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl[ \frac{c_s^2}{K_e} \biggr]^{1/2}
\biggl[ \rho_0 \biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2} \biggr]^{1 / 6}\rho_0^{- 1 / 2}
</math>
  </td>
</tr>
<tr>
  <td align="right">&nbsp;</td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 2} \rho_0e^{-\psi_i} \biggr]^{1/3}
\biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{1 / 6}e^{-\psi_i / 6} \theta_i^{-1 / 4} \biggr]\rho_0^{- 1 / 3}
</math>
  </td>
</tr>
<tr>
  <td align="right">&nbsp;</td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr) e^{-\psi_i/ 2} 
\theta_i^{-1 / 4}
\, .
</math>
  </td>
</tr>
</table>
And, finally,
<table border="0" align="center" cellpadding="8">
<tr>
  <td align="right">
<math>
\biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_i
</math>
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\frac{1}{4\pi}\biggl[ \frac{c_s^6}{4\pi G^3\rho_0} \biggr]^{1/2}
\biggl[ \frac{4\pi G}{(5 / 2)K_e} \biggr]^{3/2}
\biggl[\rho_e\biggr]^{- 1 / 2}
\biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)_i
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{3 / 2}\rho_0^{- 1 / 2}
\biggl[ \frac{c_s^2}{K_e} \biggr]^{3/2}
\biggl[\rho_0 \biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2}\biggr]^{- 1 / 2}
\biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)_i
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{3 / 2}\rho_0^{- 1 }
\biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 2} \rho_0e^{-\psi_i} \biggr]
\biggl[\biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2}\biggr]^{- 1 / 2}
\biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)_i
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{3 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{2} e^{-\psi_i / 2} \theta_i^{3 / 4}
\biggl( \xi^2 \frac{d\psi}{d\xi} \biggr)_i
</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\Rightarrow ~~~
\biggl(-\frac{d\theta}{d\eta} \biggr)_i
</math>
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{3 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{2} e^{-\psi_i / 2} \theta_i^{3 / 4}
\biggl( \frac{d\psi}{d\xi} \biggr)_i
\biggl[ \biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr) e^{-\psi_i/ 2} 
\theta_i^{-1 / 4}
\biggr]^{-2}
</math>
  </td>
</tr>
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{1 / 2}
e^{+ \psi_i / 2} \theta_i^{5 / 4}
\biggl( \frac{d\psi}{d\xi} \biggr)_i
\, .
</math>
  </td>
</tr>
</table>
<table border="1" align="center" cellpadding="8">
<tr>
  <td align="center" colspan="3">Summary Interface Relations</td>
</tr>
<tr>
  <td align="center" colspan="1">Our Derivations</td>
  <td align="center" colspan="1">After setting <math>\rho_e = \rho_0</math></td>
  <td align="center" colspan="1">Presented by {{ Yabushita75 }}<br />(after setting <math>\mu_e/\mu_c = 1</math>)</td>
</tr>
<tr>
<!-- One follows -->
  <td align="center" colspan="1">
<table border="0" align="center" cellpadding="8">
<tr>
  <td align="right"><math>\frac{\rho_e}{\rho_0}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \theta_i^{-3 / 2}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\frac{c_s^2}{K_e}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl[
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 2} \rho_0e^{-\psi_i}
\biggr]^{2 / 3}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\frac{\eta_i}{\xi_i}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr) e^{-\psi_i/ 2} 
\theta_i^{-1 / 4}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>
\biggl(-\frac{d\theta}{d\eta} \biggr)_i
</math>
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>\biggl(\frac{2}{5}\biggr)^{1 / 2}
e^{+ \psi_i / 2} \theta_i^{5 / 4}
\biggl( \frac{d\psi}{d\xi} \biggr)_i
\, .
</math>
  </td>
</tr>
</table>
  </td>
<!-- Two follows: -->
  <td align="center" colspan="1">
<table border="0" align="center" cellpadding="8">
<tr>
  <td align="right"><math>\theta_i^{3 / 2}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\biggl[ \frac{c_s^2}{K_e} \biggr]^{3}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 } \biggl[\rho_0e^{-\psi_i} \biggr]^{2}
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right"><math>\frac{\eta_i}{\xi_i}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr) e^{-\psi_i/ 2} 
\biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \biggr]^{-1 / 6}
=
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 6} e^{-\psi_i/ 3} 
\, ;
</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>
\biggl(-\frac{d\theta}{d\eta} \biggr)_i
</math>
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl( \frac{d\psi}{d\xi} \biggr)_i
e^{+ \psi_i / 2} \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)e^{-\psi_i} \biggr]^{5 / 6}
=
\biggl(\frac{2}{5}\biggr)^{1 / 2}
\biggl( \frac{d\psi}{d\xi} \biggr)_i
e^{- \psi_i / 3} \biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 6}
\, .
</math>
  </td>
</tr>
</table>
  </td>
<!-- Three follows -->
  <td align="center" colspan="1">
<table border="0" align="center" cellpadding="8">
<tr>
  <td align="right"><math>\theta_i^{3 / 2}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
e^{-\psi_i}
\, ;
</math>
  </td>
  <td align="right" width="5%">(2.9)</td>
</tr>
<tr>
  <td align="right"><math>\biggl[ \frac{c_s^2}{K_e} \biggr]^{3 / 2}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\lambda_c e^{-\psi_i}
\, ;
</math>
  </td>
  <td align="right" width="5%">(2.11)</td>
</tr>
<tr>
  <td align="right"><math>\frac{\eta_i}{\xi_i}</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{2}{5}\biggr)^{1 / 2}e^{-\psi_i/ 3}
\, ;
</math>
  </td>
  <td align="right" width="5%">(2.12)</td>
</tr>
<tr>
  <td align="right">
<math>
\biggl(\frac{d\theta}{d\eta} \biggr)_i
</math>
  </td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
-\biggl(\frac{2}{5}\biggr)^{1 / 2} \biggl( \frac{d\psi}{d\xi} \biggr)_i e^{- \psi_i / 3}
\, .
</math>
  </td>
  <td align="right" width="5%">(2.13)</td>
</tr>
</tr>
</table>
</table>
  </td>
</tr>
</table>
===Step 8: Throughout the Envelope===
Throughout the envelope, we seek the solution, <math>\theta(\eta)</math>, of the following Lane-Emden equation:
<div align="center">
<math>
\frac{1}{\eta^2} \frac{d}{d\eta} \biggl( \eta^2 \frac{d\theta}{d\eta} \biggr) = - \theta^{3 / 2} \, .
</math>
</div>
</div>
After adopting the substitute notation, <math>c_s^2 \rightarrow K_1</math> and <math>\rho_0 \rightarrow \lambda_c</math>, it is clear that these last four parameter-profile expressions are identical to the ones that appear, respectively, as equations (2.2), (2.1) and (2.3) of {{ Yabushita75 }}.  
 
For the envelope, the [[SSC/Structure/BiPolytropes#Setup|associated key parameter relations]] are:
<table border="0" align="center" cellpadding="3">
 
<tr>
  <td align="right">
<math>\rho</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\rho_e \theta^{3 / 2}</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>P</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>K_e \rho_e^{5 / 3} \theta^{5 / 2}</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{(5/2)K_e}{4\pi G} \biggr]^{1/2} \rho_e^{- 1 / 6} \eta</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>M_r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{(5/2)K_e}{4\pi G} \biggr]^{3/2} \rho_e^{1 / 2} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)</math>
  </td>
</tr>
</table>
The surface occurs where the polytropic Lane-Emden function, <math>\theta</math>, first goes to zero.  We will denote the radius at which this occurs as <math>\eta_s</math> &#8212; {{ Yabushita75 }} denotes the same radial location by <math>\eta_1</math> &#8212; and the slope of the function at the surface will be denoted as <math>(d\theta/d\eta)_s</math>.
 
===Normalizations===
 
Following {{ Yabushita75 }}, along our model sequence we will hold <math>c_s^2</math> and <math>K_e</math> fixed.  From the summary interface relations, then, we find that,
<table border="0" align="center" cellpadding="8">
 
<tr>
  <td align="right"><math>\biggl[ \frac{c_s^2}{K_e} \biggr]^{3}
</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 } \biggl[\rho_0e^{-\psi_i} \biggr]^{2}
</math>
  </td>
</tr>
 
<tr>
  <td align="right"><math>\Rightarrow ~~~\rho_0</math></td>
  <td align="center"><math>=</math></td>
  <td align="left">
<math>
\biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 2} \biggl[ \frac{c_s^2}{K_e} \biggr]^{3 / 2} e^{\psi_i}
\, .
</math>
  </td>
</tr>
</table>
This is identical to Eq. (3.1) of {{ Yabushita75 }} if we assume (as did {{ Yabushita75hereafter }}) that <math>\mu_e/\mu_c = 1</math>. Given that, following {{ Yabushita75hereafter }}, we have set <math>\rho_e = \rho_c</math>, the radius of the equilibrium configuration is given by the expression,
 
<table border="0" align="center" cellpadding="8">
 
<tr>
  <td align="right">
<math>R^2</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{5K_e}{8\pi G} \biggr] \rho_e^{- 1 / 3} \eta_s^2</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>
\frac{5K_e}{8\pi G}  \biggl[\biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 2}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 2} e^{\psi_i} \biggr]^{- 1 / 3} \eta_s^2
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>
\frac{5K_e}{8\pi G}  \biggl[\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 6}
\biggl( \frac{c_s^2}{K_e} \biggr)^{- 1 / 2} e^{- \psi_i/3} \biggr] \eta_s^2
\, ;
</math>
  </td>
</tr>
</table>
and the configuration's total mass is,
 
<table border="0" align="center" cellpadding="8">
 
<tr>
  <td align="right">
<math>M_\mathrm{tot}</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{5K_e}{8\pi G} \biggr]^{3/2} \biggl[ \rho_e \biggr]^{1 / 2} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_s</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{5K_e}{8\pi G} \biggr]^{3/2} \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 2}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 2} e^{\psi_i}  \biggr]^{1 / 2} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_s
\, .
</math>
  </td>
</tr>
</table>
If we again set <math>\mu_e/\mu_c = 1</math>, this expression is identical to Eq. (3.2) of {{ Yabushita75 }}. The configuration's mean density is,
 
<table border="0" align="center" cellpadding="8">
 
<tr>
  <td align="right">
<math>\bar\rho \equiv \frac{3M_\mathrm{tot}}{4\pi R^3} </math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>3\biggl[ \frac{5K_e}{8\pi G} \biggr]^{3/2} \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 2}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 2} e^{\psi_i}  \biggr]^{1 / 2} \biggl(-\eta^2 \frac{d\theta}{d\eta} \biggr)_s
\biggl\{
\frac{5K_e}{8\pi G}  \biggl[\biggl(\frac{\mu_e}{\mu_c}\biggr)^{5 / 6}
\biggl( \frac{c_s^2}{K_e} \biggr)^{- 1 / 2} e^{- \psi_i/3} \biggr] \eta_s^2
\biggr\}^{-3 / 2}
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>3 \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 4}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 4} e^{+\psi_i / 2}  \biggr] \biggl(-\frac{1}{\eta} \cdot \frac{d\theta}{d\eta} \biggr)_s
\biggl[\biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 4}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 4} e^{+ \psi_i/2} \biggr]
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
&nbsp;
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>3 \biggl[ \biggl(\frac{\mu_e}{\mu_c}\biggr)^{- 5 / 2}
\biggl( \frac{c_s^2}{K_e} \biggr)^{3 / 2} e^{+\psi_i }  \biggr] \biggl(-\frac{1}{\eta} \cdot \frac{d\theta}{d\eta} \biggr)_s
</math>
  </td>
</tr>
 
<tr>
  <td align="right">
<math>\Rightarrow ~~~ \frac{\bar\rho}{\rho_0}</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>3
\biggl(-\frac{1}{\eta} \cdot \frac{d\theta}{d\eta} \biggr)_s
\, .
</math>
  </td>
</tr>
</table>


=See Also=
=See Also=

Latest revision as of 18:37, 10 November 2023


Stability of a BiPolytrope with an Isothermal Core

This analysis pulls largely from 📚 S. Yabushita (1975, MNRAS, Vol. 172, pp. 441 - 453); the focus is on bipolytropes having (nc,ne)=(,32). In an accompanying discussion, we summarize the steps that Yabushita took — from 1968 and 1974, to 1975 — that led up to his discovery of an analytic description of the isothermal displacement function.

Equilibrium Structure

We will follow the accompanying formal recipe for building a bipolytropic model, using the step-by-step construction of Milne's (1930) configurations as a guide.

Step 1

The 📚 Yabushita (1975) bipolytrope has an isothermal core (nc=) and an ne=32 polytropic envelope.

Steps 2 & 3

Throughout the core, the properties of this bipolytrope can be expressed in terms of the Lane-Emden function, ψ(χ), which derives from a solution of the 2nd-order ODE,

Isothermal Lane-Emden Equation

1ξ2ddξ(ξ2dψdξ)=eψ

subject to the boundary conditions,

ψ=1       and       dψdξ=0       at       ξ=0.

As has been demonstrated in our accompanying mathematics appendix, a series expansion about the center of the isothermal configuration gives,

ψ(ξ)

=

ξ26ξ4120+ξ6189061ξ81,632,960+.

The solution, ψ(ξ), extends to infinity, so the interface between the core and the envelope can be positioned anywhere within the range, 0<ξi<.

Step4: Throughout the core

Specify: cs2 and ρ0

r

=

[cs24πGρ0]1/2ξ

(2.2)

ρ

=

ρ0eψ

(2.2)

P

=

cs2ρ0eψ

(2.1)

Mr

=

[cs64πG3ρ0]1/2(ξ2dψdξ)

(2.3)
📚 Yabushita (1975), § 2, pp. 442-443

After adopting the substitute notation, cs2K1 and ρ0λc, it is clear that these last four parameter-profile expressions are identical to the ones that appear, respectively, as equations (2.2), (2.1) and (2.3) of 📚 Yabushita (1975).

Step 5: Interface Conditions

(ρ0μc)eψi

=

(ρeμe)θine

=

(ρeμe)θi3/2

cs2ρ0eψi

=

Keρe1+1/neθine+1

=

Keρe5/3θi5/2

[cs24πGρ0]1/2ξi

=

[(ne+1)Ke4πG]1/2ρe(1ne)/(2ne)ηi

=

[(5/2)Ke4πG]1/2ρe(1/6)ηi

[cs64πG3ρ0]1/2(ξ2dψdξ)i

=

4π[(ne+1)Ke4πG]3/2ρe(3ne)/(2ne)(η2dθdη)i

=

4π[(5/2)Ke4πG]3/2ρe1/2(η2dθdη)i

This means that,

ρeρ0 =

(μeμc)eψiθi3/2;

Ke[ρ0(μeμc)eψiθi3/2]5/3θi5/2 =

cs2ρ0eψi

Keρ02/3cs2 =

(μeμc)5/3e+2ψi/3

cs2Ke =

[(μeμc)5/2ρ0eψi]2/3;

ηiξi =

[cs24πGρ0]1/2[4πG(5/2)Ke]1/2[ρe]1/6

  =

(25)1/2[cs2Ke]1/2[ρ0(μeμc)eψiθi3/2]1/6ρ01/2

  =

(25)1/2[(μeμc)5/2ρ0eψi]1/3[(μeμc)1/6eψi/6θi1/4]ρ01/3

  =

(25)1/2(μeμc)eψi/2θi1/4.

And, finally,

(η2dθdη)i

=

14π[cs64πG3ρ0]1/2[4πG(5/2)Ke]3/2[ρe]1/2(ξ2dψdξ)i

 

=

(25)3/2ρ01/2[cs2Ke]3/2[ρ0(μeμc)eψiθi3/2]1/2(ξ2dψdξ)i

 

=

(25)3/2ρ01[(μeμc)5/2ρ0eψi][(μeμc)eψiθi3/2]1/2(ξ2dψdξ)i

 

=

(25)3/2(μeμc)2eψi/2θi3/4(ξ2dψdξ)i

(dθdη)i

=

(25)3/2(μeμc)2eψi/2θi3/4(dψdξ)i[(25)1/2(μeμc)eψi/2θi1/4]2

 

=

(25)1/2e+ψi/2θi5/4(dψdξ)i.

Summary Interface Relations
Our Derivations After setting ρe=ρ0 Presented by 📚 Yabushita (1975)
(after setting μe/μc=1)
ρeρ0 =

(μeμc)eψiθi3/2;

cs2Ke =

[(μeμc)5/2ρ0eψi]2/3;

ηiξi =

(25)1/2(μeμc)eψi/2θi1/4;

(dθdη)i

=

(25)1/2e+ψi/2θi5/4(dψdξ)i.

θi3/2 =

(μeμc)eψi;

[cs2Ke]3 =

(μeμc)5[ρ0eψi]2;

ηiξi =

(25)1/2(μeμc)eψi/2[(μeμc)eψi]1/6=(25)1/2(μeμc)5/6eψi/3;

(dθdη)i

=

(25)1/2(dψdξ)ie+ψi/2[(μeμc)eψi]5/6=(25)1/2(dψdξ)ieψi/3(μeμc)5/6.

θi3/2 =

eψi;

(2.9)
[cs2Ke]3/2 =

λceψi;

(2.11)
ηiξi =

(25)1/2eψi/3;

(2.12)

(dθdη)i

=

(25)1/2(dψdξ)ieψi/3.

(2.13)

Step 8: Throughout the Envelope

Throughout the envelope, we seek the solution, θ(η), of the following Lane-Emden equation:

1η2ddη(η2dθdη)=θ3/2.

For the envelope, the associated key parameter relations are:

ρ

=

ρeθ3/2

P

=

Keρe5/3θ5/2

r

=

[(5/2)Ke4πG]1/2ρe1/6η

Mr

=

4π[(5/2)Ke4πG]3/2ρe1/2(η2dθdη)

The surface occurs where the polytropic Lane-Emden function, θ, first goes to zero. We will denote the radius at which this occurs as ηs📚 Yabushita (1975) denotes the same radial location by η1 — and the slope of the function at the surface will be denoted as (dθ/dη)s.

Normalizations

Following 📚 Yabushita (1975), along our model sequence we will hold cs2 and Ke fixed. From the summary interface relations, then, we find that,

[cs2Ke]3 =

(μeμc)5[ρ0eψi]2

ρ0 =

(μeμc)5/2[cs2Ke]3/2eψi.

This is identical to Eq. (3.1) of 📚 Yabushita (1975) if we assume (as did Yabushita75) that μe/μc=1. Given that, following Yabushita75, we have set ρe=ρc, the radius of the equilibrium configuration is given by the expression,

R2

=

[5Ke8πG]ρe1/3ηs2

 

=

5Ke8πG[(μeμc)5/2(cs2Ke)3/2eψi]1/3ηs2

 

=

5Ke8πG[(μeμc)5/6(cs2Ke)1/2eψi/3]ηs2;

and the configuration's total mass is,

Mtot

=

4π[5Ke8πG]3/2[ρe]1/2(η2dθdη)s

 

=

4π[5Ke8πG]3/2[(μeμc)5/2(cs2Ke)3/2eψi]1/2(η2dθdη)s.

If we again set μe/μc=1, this expression is identical to Eq. (3.2) of 📚 Yabushita (1975). The configuration's mean density is,

ρ¯3Mtot4πR3

=

3[5Ke8πG]3/2[(μeμc)5/2(cs2Ke)3/2eψi]1/2(η2dθdη)s{5Ke8πG[(μeμc)5/6(cs2Ke)1/2eψi/3]ηs2}3/2

 

=

3[(μeμc)5/4(cs2Ke)3/4e+ψi/2](1ηdθdη)s[(μeμc)5/4(cs2Ke)3/4e+ψi/2]

 

=

3[(μeμc)5/2(cs2Ke)3/2e+ψi](1ηdθdη)s

ρ¯ρ0

=

3(1ηdθdη)s.

See Also


Tiled Menu

Appendices: | VisTrailsEquations | VisTrailsVariables | References | Ramblings | VisTrailsImages | myphys.lsu | ADS |