Appendix/Ramblings/51BiPolytropeStability/RethinkEnvelope: Difference between revisions

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<tr>
<tr>
   <td align="center">
   <td align="center">
<math>n = n_c</math>
<math>n_c = 5</math>
   </td>
   </td>
   <td align="center">
   <td align="center">
<math>n = n_e</math>
<math>n_e = 1</math>
   </td>
   </td>
</tr>
</tr>
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   <td align="center">
<math>
<math>
\frac{1}{\xi^2} \frac{d}{d\xi} \biggl( \xi^2 \frac{d\theta}{d\xi} \biggr) = - \theta^{n_c}
\frac{1}{\xi^2} \frac{d}{d\xi} \biggl( \xi^2 \frac{d\theta}{d\xi} \biggr) = - \theta^{5}
</math>
</math>


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   <td align="center">
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<math>
<math>
\frac{1}{\eta^2} \frac{d}{d\eta} \biggl( \eta^2 \frac{d\phi}{d\eta} \biggr) = - \phi^{n_e}
\frac{1}{\eta^2} \frac{d}{d\eta} \biggl( \eta^2 \frac{d\phi}{d\eta} \biggr) = - \phi
</math>
</math>


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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>\rho_0 \theta^{n_c}</math>
<math>\rho_0 \theta^{5}</math>
   </td>
   </td>
</tr>
</tr>
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   </td>
   </td>
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   <td align="left">
<math>K_c \rho_0^{1+1/n_c} \theta^{n_c + 1}</math>
<math>K_c \rho_0^{6/5} \theta^{6}</math>
   </td>
   </td>
</tr>
</tr>
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>\biggl[ \frac{(n_c + 1)K_c}{4\pi G} \biggr]^{1/2} \rho_0^{(1-n_c)/(2n_c)} \xi</math>
<math>\biggl[ \frac{3K_c}{2\pi G} \biggr]^{1/2} \rho_0^{-2/5} \xi</math>
   </td>
   </td>
</tr>
</tr>
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   </td>
   </td>
   <td align="left">
   <td align="left">
<math>4\pi \biggl[ \frac{(n_c + 1)K_c}{4\pi G} \biggr]^{3/2} \rho_0^{(3-n_c)/(2n_c)} \biggl(-\xi^2 \frac{d\theta}{d\xi} \biggr)</math>
<math>4\pi \biggl[ \frac{3K_c}{2\pi G} \biggr]^{3/2} \rho_0^{-1/5} \biggl(-\xi^2 \frac{d\theta}{d\xi} \biggr)</math>
   </td>
   </td>
</tr>
</tr>

Revision as of 18:34, 28 May 2023

Rethink Handling of n = 1 Envelope

Solution Steps

Drawing from an accompanying discussion

  • Step 1: Choose nc and ne.
  • Step 2: Adopt boundary conditions at the center of the core (θ=1 and dθ/dξ=0 at ξ=0), then solve the Lane-Emden equation to obtain the solution, θ(ξ), and its first derivative, dθ/dξ throughout the core; the radial location, ξ=ξs, at which θ(ξ) first goes to zero identifies the natural surface of an isolated polytrope that has a polytropic index nc.
  • Step 3 Choose the desired location, 0<ξi<ξs, of the outer edge of the core.
  • Step 4: Specify Kc and ρ0; the structural profile of, for example, ρ(r), P(r), and Mr(r) is then obtained throughout the core — over the radial range, 0ξξi and 0rri — via the relations shown in the 2nd column of Table 1.
  • Step 5: Specify the ratio μe/μc and adopt the boundary condition, ϕi=1; then use the interface conditions as rearranged and presented in Table 3 to determine, respectively:
    • The gas density at the base of the envelope, ρe;
    • The polytropic constant of the envelope, Ke, relative to the polytropic constant of the core, Kc;
    • The ratio of the two dimensionless radial parameters at the interface, ηi/ξi;
    • The radial derivative of the envelope solution at the interface, (dϕ/dη)i.
  • Step 6: The last sub-step of solution step 5 provides the boundary condition that is needed — in addition to our earlier specification that ϕi=1 — to derive the desired particular solution, ϕ(η), of the Lane-Emden equation that is relevant throughout the envelope; knowing ϕ(η) also provides the relevant structural first derivative, dϕ/dη, throughout the envelope.
  • Step 7: The surface of the bipolytrope will be located at the radial location, η=ηs and r=R, at which ϕ(η) first drops to zero.
  • Step 8: The structural profile of, for example, ρ(r), P(r), and Mr(r) is then obtained throughout the envelope — over the radial range, ηiηηs and rirR — via the relations provided in the 3rd column of Table 1.

Setup

Drawing from the accompanying Table 1, we have …

Core

Envelope

nc=5

ne=1

1ξ2ddξ(ξ2dθdξ)=θ5

sol'n: θ(ξ)

1η2ddη(η2dϕdη)=ϕ

sol'n: ϕ(η)

Specify: Kc and ρ0

ρ

=

ρ0θ5

P

=

Kcρ06/5θ6

r

=

[3Kc2πG]1/2ρ02/5ξ

Mr

=

4π[3Kc2πG]3/2ρ01/5(ξ2dθdξ)

Knowing: Ke and ρe

ρ

=

ρeϕne

P

=

Keρe1+1/neϕne+1

r

=

[(ne+1)Ke4πG]1/2ρe(1ne)/(2ne)η

Mr

=

4π[(ne+1)Ke4πG]3/2ρe(3ne)/(2ne)(η2dϕdη)

See Also

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