Appendix/Ramblings/51BiPolytropeStability/RethinkEnvelope: Difference between revisions

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Created page with "__FORCETOC__ =Rethink Handling of n = 1 Envelope= ==Solution Steps== Drawing from an accompanying discussion … * Step 1: Choose <math>n_c</math> and <math>n_e</math>. * Step 2: Adopt boundary conditions at the center of the core (<math>\theta = 1</math> and <math>d\theta/d\xi = 0</math> at <math>\xi=0</math>), then solve the Lane-Emden equation to obtain the solution, <math>\theta(\xi)</math>, and its first derivati..."
 
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* Step 8:  The structural profile of, for example, <math>\rho(r)</math>, <math>P(r)</math>, and <math>M_r(r)</math> is then obtained throughout the envelope &#8212; over the radial range, <math>\eta_i \le \eta \le \eta_s</math> and <math>r_i \le r \le R</math> &#8212; via the relations provided in the <math>3^\mathrm{rd}</math> column of Table 1.
* Step 8:  The structural profile of, for example, <math>\rho(r)</math>, <math>P(r)</math>, and <math>M_r(r)</math> is then obtained throughout the envelope &#8212; over the radial range, <math>\eta_i \le \eta \le \eta_s</math> and <math>r_i \le r \le R</math> &#8212; via the relations provided in the <math>3^\mathrm{rd}</math> column of Table 1.


==Setup==
Drawing from the [[SSC/Structure/BiPolytropes#Setup|accompanying Table 1]], we have &hellip;
<table border="1" cellpadding="5" width="80%" align="center">
<tr>
  <td align="center" colspan="2">
<font size="+1" color="darkblue">
'''Core'''
</font>
  </td>
  <td align="center">
<font size="+1" color="darkblue">
'''Envelope'''
</font>
  </td>
</tr>
<tr>
  <td align="center">
Isothermal <math>(n_c = \infty)</math>
  </td>
  <td align="center">
<math>n = n_c</math>
  </td>
  <td align="center">
<math>n = n_e</math>
  </td>
</tr>
<tr>
  <td align="center">
<math>
\frac{1}{\chi^2} \frac{d}{d\chi} \biggl( \chi^2 \frac{d\psi}{d\chi} \biggr) = e^{-\psi}
</math>
sol'n:
<math>
\psi(\chi)
</math>
  </td>
  <td align="center">
<math>
\frac{1}{\xi^2} \frac{d}{d\xi} \biggl( \xi^2 \frac{d\theta}{d\xi} \biggr) = - \theta^{n_c}
</math>
sol'n:
<math>
\theta(\xi)
</math>
  </td>
  <td align="center">
<math>
\frac{1}{\eta^2} \frac{d}{d\eta} \biggl( \eta^2 \frac{d\phi}{d\eta} \biggr) = - \phi^{n_e}
</math>
sol'n:
<math>
\phi(\eta)
</math>
  </td>
</tr>
<tr>
  <td align="center">
<!-- BEGIN LEFT BLOCK details -->
<table border="0" cellpadding="3">
<tr>
  <td align="center" colspan="3">
Specify:  <math>c_s^2</math> and <math>\rho_0 ~\Rightarrow</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\rho</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\rho_0 e^{-\psi}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>P</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>c_s^2 \rho_0 e^{-\psi}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{c_s^2}{4\pi G\rho_0} \biggr]^{1/2} \chi</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>M_r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{c_s^6}{4\pi G^3\rho_0} \biggr]^{1/2} \biggl( \chi^2 \frac{d\psi}{d\chi} \biggr)</math>
  </td>
</tr>
</table>
<!-- END LEFT BLOCK details -->
  </td>
  <td align="center">
<!-- BEGIN CENTER BLOCK details -->
<table border="0" cellpadding="3">
<tr>
  <td align="center" colspan="3">
Specify:  <math>K_c</math> and <math>\rho_0 ~\Rightarrow</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\rho</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\rho_0 \theta^{n_c}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>P</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>K_c \rho_0^{1+1/n_c} \theta^{n_c + 1}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{(n_c + 1)K_c}{4\pi G} \biggr]^{1/2} \rho_0^{(1-n_c)/(2n_c)} \xi</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>M_r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{(n_c + 1)K_c}{4\pi G} \biggr]^{3/2} \rho_0^{(3-n_c)/(2n_c)} \biggl(-\xi^2 \frac{d\theta}{d\xi} \biggr)</math>
  </td>
</tr>
</table>
<!-- END CENTER BLOCK details -->
  </td>
  <td align="center">
<!-- BEGIN RIGHT BLOCK details -->
<table border="0" cellpadding="3">
<tr>
  <td align="center" colspan="3">
Knowing:  <math>K_e</math> and <math>\rho_e ~\Rightarrow</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>\rho</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\rho_e \phi^{n_e}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>P</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>K_e \rho_e^{1+1/n_e} \phi^{n_e + 1}</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>\biggl[ \frac{(n_e + 1)K_e}{4\pi G} \biggr]^{1/2} \rho_e^{(1-n_e)/(2n_e)} \eta</math>
  </td>
</tr>
<tr>
  <td align="right">
<math>M_r</math>
  </td>
  <td align="center">
<math>=</math>
  </td>
  <td align="left">
<math>4\pi \biggl[ \frac{(n_e + 1)K_e}{4\pi G} \biggr]^{3/2} \rho_e^{(3-n_e)/(2n_e)} \biggl(-\eta^2 \frac{d\phi}{d\eta} \biggr)</math>
  </td>
</tr>
</table>
<!-- END RIGHT BLOCK details -->
  </td>
</tr>
</table>


=See Also=
=See Also=

Revision as of 18:25, 28 May 2023

Rethink Handling of n = 1 Envelope

Solution Steps

Drawing from an accompanying discussion

  • Step 1: Choose nc and ne.
  • Step 2: Adopt boundary conditions at the center of the core (θ=1 and dθ/dξ=0 at ξ=0), then solve the Lane-Emden equation to obtain the solution, θ(ξ), and its first derivative, dθ/dξ throughout the core; the radial location, ξ=ξs, at which θ(ξ) first goes to zero identifies the natural surface of an isolated polytrope that has a polytropic index nc.
  • Step 3 Choose the desired location, 0<ξi<ξs, of the outer edge of the core.
  • Step 4: Specify Kc and ρ0; the structural profile of, for example, ρ(r), P(r), and Mr(r) is then obtained throughout the core — over the radial range, 0ξξi and 0rri — via the relations shown in the 2nd column of Table 1.
  • Step 5: Specify the ratio μe/μc and adopt the boundary condition, ϕi=1; then use the interface conditions as rearranged and presented in Table 3 to determine, respectively:
    • The gas density at the base of the envelope, ρe;
    • The polytropic constant of the envelope, Ke, relative to the polytropic constant of the core, Kc;
    • The ratio of the two dimensionless radial parameters at the interface, ηi/ξi;
    • The radial derivative of the envelope solution at the interface, (dϕ/dη)i.
  • Step 6: The last sub-step of solution step 5 provides the boundary condition that is needed — in addition to our earlier specification that ϕi=1 — to derive the desired particular solution, ϕ(η), of the Lane-Emden equation that is relevant throughout the envelope; knowing ϕ(η) also provides the relevant structural first derivative, dϕ/dη, throughout the envelope.
  • Step 7: The surface of the bipolytrope will be located at the radial location, η=ηs and r=R, at which ϕ(η) first drops to zero.
  • Step 8: The structural profile of, for example, ρ(r), P(r), and Mr(r) is then obtained throughout the envelope — over the radial range, ηiηηs and rirR — via the relations provided in the 3rd column of Table 1.

Setup

Drawing from the accompanying Table 1, we have …

Core

Envelope

Isothermal (nc=)

n=nc

n=ne

1χ2ddχ(χ2dψdχ)=eψ

sol'n: ψ(χ)

1ξ2ddξ(ξ2dθdξ)=θnc

sol'n: θ(ξ)

1η2ddη(η2dϕdη)=ϕne

sol'n: ϕ(η)

Specify: cs2 and ρ0

ρ

=

ρ0eψ

P

=

cs2ρ0eψ

r

=

[cs24πGρ0]1/2χ

Mr

=

[cs64πG3ρ0]1/2(χ2dψdχ)

Specify: Kc and ρ0

ρ

=

ρ0θnc

P

=

Kcρ01+1/ncθnc+1

r

=

[(nc+1)Kc4πG]1/2ρ0(1nc)/(2nc)ξ

Mr

=

4π[(nc+1)Kc4πG]3/2ρ0(3nc)/(2nc)(ξ2dθdξ)

Knowing: Ke and ρe

ρ

=

ρeϕne

P

=

Keρe1+1/neϕne+1

r

=

[(ne+1)Ke4πG]1/2ρe(1ne)/(2ne)η

Mr

=

4π[(ne+1)Ke4πG]3/2ρe(3ne)/(2ne)(η2dϕdη)

See Also

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