SSC/Structure/BiPolytropes/51RenormaizePart3: Difference between revisions

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<math>
<math>
\biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-5 / 4} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-3 / 2} \theta^{-5}_i \biggr]
\biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-5 / 4} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-3 / 2} \biggr]\phi
\theta^{5}_i \phi
</math>
</math>
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<math>K_c \biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-5 / 4} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-5 / 2} \theta^{-5}_i \biggr]^{6/5}  
<math>K_c \biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-3 / 2} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-3} \biggr]  \phi^{2}</math>
\theta^{6}_i \phi^{2}</math>
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<math>\biggl[ \frac{K_c}{G } \biggr]^{1/2}  
<math>\biggl[ \frac{K_c}{G } \biggr]^{1/2}  
\biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-5 / 4} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-5 / 2} \theta^{-5}_i \biggr]^{- 2 / 5}
\biggl( \frac{K_e}{K_c} \biggr)^{1 / 2} (2\pi)^{-1/2}\eta</math>
\biggl( \frac{\mu_e}{\mu_c} \biggr)^{-1} \theta^{-2}_i (2\pi)^{-1/2}\eta</math>
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<math>\biggl[ \frac{K_c^3}{G^3 } \biggr]^{1/2}  
<math>\biggl[ \frac{K_c^3}{G^3 } \biggr]^{1/2}  
\biggl[ \biggl( \frac{K_e}{K_c} \biggr)^{-5 / 4} \biggl( \frac{\mu_e}{\mu_c} \biggr)^{-5 / 2} \theta^{-5}_i \biggr]^{-1 / 5}
\biggl( \frac{K_e}{K_c} \biggr)^{1 / 4}  
\biggl( \frac{\mu_e}{\mu_c} \biggr)^{-2} \theta^{-1}_i \biggl( \frac{2}{\pi} \biggr)^{1/2} \biggl(-\eta^2 \frac{d\phi}{d\eta} \biggr)</math>
\biggl( \frac{\mu_e}{\mu_c} \biggr)^{-3 / 2} \biggl( \frac{2}{\pi} \biggr)^{1/2} \biggl(-\eta^2 \frac{d\phi}{d\eta} \biggr)</math>
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Revision as of 21:38, 10 November 2023


BiPolytrope with nc = 5 and ne = 1

After studying 📚 S. Yabushita (1975, MNRAS, Vol. 172, pp. 441 - 453) in depth, here we renormalize our original construction of bipolytropic models with (nc,ne)=(5,1) such that both entropy values, (Kc,Ke), are held fixed along each model sequence.

Original Derivation

Throughout the Core

Drawing from our original derivation, throughout the core

Specify: Kc and ρ0

 

ρ

=

ρ0θnc

=

ρ0(1+13ξ2)5/2

P

=

Kcρ01+1/ncθnc+1

=

Kcρ06/5(1+13ξ2)3

r

=

[(nc+1)Kc4πG]1/2ρ0(1nc)/(2nc)ξ

=

[KcGρ04/5]1/2(32π)1/2ξ

Mr

=

4π[(nc+1)Kc4πG]3/2ρ0(3nc)/(2nc)(ξ2dθdξ)

=

[Kc3G3ρ02/5]1/2(23π)1/2[ξ3(1+13ξ2)3/2]

Throughout the Envelope

And throughout the envelope,

 

Knowing: Ke/Kc and ρe/ρ0 from Step 5  

ρ

=

ρeϕne

=

ρ0(ρeρ0)ϕ

=

ρ0(μeμc)θi5ϕ

P

=

Keρe1+1/neϕne+1

=

Kcρ06/5(Keρ04/5Kc)(ρeρ0)2ϕ2

=

Kcρ06/5θi6ϕ2

r

=

[(ne+1)Ke4πG]1/2ρe(1ne)/(2ne)η

=

[KcGρ04/5]1/2(Keρ04/5Kc)1/2(2π)1/2η

=

[KcGρ04/5]1/2(μeμc)1θi2(2π)1/2η

Mr

=

4π[(ne+1)Ke4πG]3/2ρe(3ne)/(2ne)(η2dϕdη)

=

[Kc3G3ρ02/5]1/2(Keρ04/5Kc)3/2(ρeρ0)(2π)1/2(η2dϕdη)

=

[Kc3G3ρ02/5]1/2(μeμc)2θi1(2π)1/2(η2dϕdη)

Interface Conditions

And at the interface

 

Setting nc=5, ne=1, and ϕi=1

ρeρ0

=

(μeμc)θincϕine

=

(μeμc)θi5

(KeKc)

=

ρ01/nc1/ne(μeμc)(1+1/ne)θi1nc/ne

=

ρ04/5(μeμc)2θi4

ηiξi

=

[nc+1ne+1]1/2(μeμc)θi(nc1)/2ϕi(1ne)/2

=

31/2(μeμc)θi2

(dϕdη)i

=

[nc+1ne+1]1/2θi(nc+1)/2ϕi(ne+1)/2(dθdξ)i

=

31/2θi3(dθdξ)i

New Normalization

From one of the interface conditions, we see that,

(KeKc)

=

ρ04/5(μeμc)2θi4

ρ0

=

[(KeKc)1(μeμc)2θi4]5/4=[(KeKc)5/4(μeμc)5/2θi5].

Hence, throughout the core, we have,

ρ

=

ρ0(1+13ξ2)5/2

=

[(KeKc)5/4(μeμc)5/2θi5](1+13ξ2)5/2

P

=

Kcρ06/5(1+13ξ2)3

=

Kc[(KeKc)5/4(μeμc)5/2θi5]6/5(1+13ξ2)3

 

=

Kc[(KeKc)3/2(μeμc)3θi6](1+13ξ2)3

r

=

[KcGρ04/5]1/2(32π)1/2ξ

=

[KcG]1/2[(KeKc)5/4(μeμc)5/2θi5]2/5(32π)1/2ξ

 

=

[KcG]1/2[(KeKc)1/2(μeμc)θi2](32π)1/2ξ

Mr

=

[Kc3G3ρ02/5]1/2(23π)1/2[ξ3(1+13ξ2)3/2]

=

[Kc3G3]1/2[(KeKc)5/4(μeμc)5/2θi5]1/5(23π)1/2[ξ3(1+13ξ2)3/2]

 

=

[Kc3G3]1/2[(KeKc)1/4(μeμc)1/2θi](23π)1/2[ξ3(1+13ξ2)3/2]

And, throughout the envelope …

ρ

=

ρ0(μeμc)θi5ϕ

=

[(KeKc)5/4(μeμc)5/2θi5](μeμc)θi5ϕ

 

=

[(KeKc)5/4(μeμc)3/2]ϕ

P

=

Kcρ06/5θi6ϕ2

=

Kc[(KeKc)5/4(μeμc)5/2θi5]6/5θi6ϕ2

 

=

Kc[(KeKc)3/2(μeμc)3]ϕ2

r

=

[KcGρ04/5]1/2(μeμc)1θi2(2π)1/2η

=

[KcG]1/2[(KeKc)5/4(μeμc)5/2θi5]2/5(μeμc)1θi2(2π)1/2η

 

=

[KcG]1/2(KeKc)1/2(2π)1/2η

Mr

=

[Kc3G3ρ02/5]1/2(μeμc)2θi1(2π)1/2(η2dϕdη)

=

[Kc3G3]1/2[(KeKc)5/4(μeμc)5/2θi5]1/5(μeμc)2θi1(2π)1/2(η2dϕdη)

 

=

[Kc3G3]1/2(KeKc)1/4(μeμc)3/2(2π)1/2(η2dϕdη)

See Also


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