SSC/Structure/BiPolytropes/Analytic1.53

BiPolytrope with (n_c, n_e) = (3/2, 3)

Milne (1930)

Here we lay out the procedure for constructing a bipolytrope in which the core has an $n_c=\frac{3}{2}$ polytropic index and the envelope has an $n_e=3$ polytropic index. We will build our discussion around the work of E. A. Milne (1930, MNRAS, 91, 4) who, as we shall see, justified these two indexes on physical grounds. While this system cannot be described by closed-form, analytic expressions, it is of particular interest because — as far as we have been able to determine — its examination by Milne represents the first "composite polytrope" to be discussed in the astrophysics literature.

In deriving the properties of this model, we will follow the general solution steps for constructing a bipolytrope that are outlined in a separate chapter of this H_Book. That group of general solution steps was drawn largely from chapter IV, §28 of Chandrasekhar's book titled, "An Introduction to the Study of Stellar Structure" [C67]. At the end of that chapter (specifically, p. 182), Chandrasekhar acknowledges that "[Milne's] method is largely used in § 28." It seems fitting, therefore, that we highlight the features of the specific bipolytropic configuration that E. A. Milne (1930) chose to build.

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Milne's (1930) Choice of Equations of State

As has been detailed in our introductory discussion of analytically expressible equations of state and as is summarized in the following table, often the total gas pressure can be expressed as the sum of three separate components: a component of ideal gas pressure, a component of radiation pressure, and a component due to a degenerate electron gas. As a result, the total pressure is given by the expression,

$P$

$=$

$P_{\mathrm{g}\mathrm{a}\mathrm{s}}+P_{\mathrm{d}\mathrm{e}\mathrm{g}}+P_{\mathrm{r}\mathrm{a}\mathrm{d}}.$

Ideal Gas	Degenerate Electron Gas	Radiation
$P_{\mathrm{g}\mathrm{a}\mathrm{s}}=\frac{\mathrm{\Re }}{\overline{\mu }}\rho T$	$P_{\mathrm{d}\mathrm{e}\mathrm{g}}=A_{\mathrm{F}}F(\chi )$ where:  $F(\chi )\equiv \chi (2{\chi }^2-3)({\chi }^2+1{)}^{1/2}+3{\sinh }^{-1}\chi$ and:    $\chi \equiv (\rho /B_{\mathrm{F}}{)}^{1/3}$	$P_{\mathrm{r}\mathrm{a}\mathrm{d}}=\frac{1}{3}{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{T}^4$

With this construction in mind, Milne (1930) also introduced the parameter, $\beta$, to define the ratio of gas pressure (meaning, ideal-gas plus degeneracy pressure) to total pressure, that is,

$\beta \equiv \frac{P_{\mathrm{g}\mathrm{a}\mathrm{s}}+P_{\mathrm{d}\mathrm{e}\mathrm{g}}}{P},$

in which case, also,

$\frac{P_{\mathrm{r}\mathrm{a}\mathrm{d}}}{P}=1-\beta$         and         $\frac{P_{\mathrm{g}\mathrm{a}\mathrm{s}}+P_{\mathrm{d}\mathrm{e}\mathrm{g}}}{P_{\mathrm{r}\mathrm{a}\mathrm{d}}}=\frac{\beta }{1-\beta }.$

(We also have referenced this parameter, β, in the context of a broader discussion of equations of state and modeling time-dependent flows.)

Envelope

Now, inside the envelope of his composite polytrope, Milne (1930) considered that the effects of electron degeneracy pressure could be ignored and, accordingly, employed throughout the envelope the expression,

$\frac{P_{\mathrm{g}\mathrm{a}\mathrm{s}}}{P_{\mathrm{r}\mathrm{a}\mathrm{d}}}{|}_{\mathrm{e}\mathrm{n}\mathrm{v}}=\frac{\beta }{1-\beta },$

or (see Milne's equation 24),

$\left(\frac{\mathrm{\Re }}{{\mu }_e}\right)\rho =\frac{1}{3}{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{T}^3\left(\frac{\beta }{1-\beta }\right).$

If the parameter, $\beta$, is constant throughout the envelope — which Milne assumes — then this last expression can be interpreted as defining a $T(\rho )$ function throughout the envelope of the form,

$T=\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta })\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/3}{\rho }^{1/3}.$

Now, returning to the definition of $\beta$ while ignoring the effects of degeneracy pressure, we recognize that the total pressure in the envelope can be written in the form of a modified ideal gas relation, namely,

$\beta P=P_{\mathrm{g}\mathrm{a}\mathrm{s}}+{\xcancel{P_{\mathrm{d}\mathrm{e}\mathrm{g}}}}^0=\left(\frac{\mathrm{\Re }}{{\mu }_e}\right)\rho T,$

with the specific $T(\rho )$ behavior just derived. This allows us to write the envelope's total pressure as,

$P$	$=$	$\frac{1}{\beta }\left(\frac{\mathrm{\Re }}{{\mu }_e}\right)\rho \left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta })\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/3}{\rho }^{1/3}$
	$=$	$\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/3}{\rho }^{1+1/3},$

which can be immediately associated with a polytropic relation of the form,

$P=K_e{\rho }^{1+1/n_e},$

with,

$n_e$	$=$	$3,$
$K_e$	$=$	$\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/3}.$

So, from the solution, $\varphi (\eta )$, to the Lane-Emden equation of index $n=3$, we will be able to determine that,

$\rho$

$=$

${\rho }_e{\varphi }^3,$

and,

$r$

$=$

$a_3\eta ,$

where — see our general introduction to the Lane-Emden equation —

$a_3^2$

$=$

$\left(\frac{K_e}{\pi G}\right){\rho }_e^{-2/3}.$

This is the envelope structure that will be incorporated into our derivation of the bipolytrope's properties, below.

In contrast to this approach, Milne (1930) chose to relate the solution to the envelope's $n=3$ Lane-Emden equation directly to the temperature via the expression,

$T=\lambda \varphi ,$

and deduced that the corresponding radial scale-factor is (see Milne's equation 27),

$a_{\mathrm{M}\mathrm{i}\mathrm{l}\mathrm{n}\mathrm{e}}^2$

$=$

$\frac{1}{{\lambda }^2}\left(\frac{\mathrm{\Re }}{{\mu }_e}{)}^2\frac{(1-\beta )}{{\beta }^2}\right(\frac{3}{\pi a_{\mathrm{r}\mathrm{a}\mathrm{d}}G}).$

In order to demonstrate the relationship between our radial scale-factor $(a_3)$ and Milne's, we note that,

${\varphi }^3$	$=$	$(\frac{T}{\lambda }{)}^3=\frac{\rho }{{\rho }_e}$
$\Rightarrow {\lambda }^3$	$=$	${\rho }_e\left(\frac{T^3}{\rho }\right)$
	$=$	${\rho }_e\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta }\left)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]$
$\Rightarrow {\lambda }^{-2}$	$=$	${\rho }_e^{-2/3}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta })\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{-2/3}.$

Hence,

$a_{\mathrm{M}\mathrm{i}\mathrm{l}\mathrm{n}\mathrm{e}}^2$	$=$	${\rho }_e^{-2/3}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta }\left)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{-2/3}\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^2\frac{(1-\beta )}{{\beta }^2}\left(\frac{3}{\pi a_{\mathrm{r}\mathrm{a}\mathrm{d}}G}\right)$
	$=$	${\rho }_e^{-2/3}\left(\frac{1}{\pi G}\right)\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\frac{(1-\beta )}{{\beta }^4}\left(\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right){]}^{1/3}$
	$=$	${\rho }_e^{-2/3}\left(\frac{K_e}{\pi G}\right).$

It is clear, therefore, that the two radial scale-factors are the same. In preparation for our further discussion of the structure of this bipolytrope's envelope, below, it is useful to highlight the following two expressions that have been developed here in the process of showing the correspondence between our work and that of Milne:

A Pair of Highlighted Relations

${\rho }_e$ $=$ ${\lambda }^3\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}\left)\right(\frac{1-\beta }{\beta })\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{-1}$   $=$ ${\lambda }^3\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^{-1}\frac{\beta }{(1-\beta )}\cdot \frac{1}{3}{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}]$ $K_e$ $=$ $\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/3}$

Core

In contrast to the envelope, Milne (1930) assumed that the (non-relativistic; "NR") electron degeneracy pressure dominates over the ideal-gas pressure in the core. That is, he assumed that, throughout the core of his composite polytropic configuration,

$\beta P={\xcancel{P_{\mathrm{g}\mathrm{a}\mathrm{s}}}}^0+P_{\mathrm{d}\mathrm{e}\mathrm{g}}{|}_{\mathrm{N}\mathrm{R}}.$

As we have demonstrated elsewhere, the non-relativistic expression for the degeneracy pressure is,

$P_{\mathrm{d}\mathrm{e}\mathrm{g}}{|}_{\mathrm{N}\mathrm{R}}$

$=$

$\frac{1}{2^2\cdot 5}\left(\frac{3}{\pi }{)}^{2/3}\right(\frac{h^2}{m_e}\left)\right[\frac{\rho }{({\mu }_{e^{-}})m_p}{]}^{5/3},$

which can be associated with a polytropic relation of the form,

$P_{\mathrm{d}\mathrm{e}\mathrm{g}}{|}_{\mathrm{N}\mathrm{R}}=K_c{\rho }^{1+1/n_c},$

that is, a total pressure of the form,

$\beta P=K_c{\rho }^{1+1/n_c},$

with,

$n_c$	$=$	$\frac{3}{2},$
$K_c$	$=$	$\frac{1}{2^2\cdot 5}\left(\frac{3}{\pi }{)}^{2/3}\right(\frac{h^2}{m_e}\left)\right[\frac{1}{({\mu }_{e^{-}})m_p}{]}^{5/3}.$

(Note that, here only, we have used the parameter, ${\mu }_{e^{-}}$, to denote the molecular weight of electrons, instead of just ${\mu }_e$, in order not to confuse it with the mean molecular weight assigned, below, to the envelope material.) So, from the solution, $\theta (\xi )$, to the Lane-Emden equation of index $n=\frac{3}{2}$, we will be able to determine that,

$\rho$

$=$

${\rho }_0{\theta }^{3/2},$

and,

$r$

$=$

$a_{3/2}\xi ,$

where — see our general introduction to the Lane-Emden equation —

$(a_{3/2}{)}^2$

$=$

$\left(\frac{5K_c}{2^3\pi G}\right){\rho }_0^{-1/3}.$

This is the core structure that will be incorporated into our derivation of the bipolytrope's properties, below.

This is precisely the approach taken by Milne (1930). Just before his equation (43), Milne states that, "the equation of state when the electrons alone are degenerate can be shown" to be,

$p$

$=$

$\frac{1}{5}(\frac{3}{4\pi }{)}^{2/3}\frac{h^2}{(2m_H{)}^{5/3}{m}_e{q}_e^{2/3}}{\rho }^{5/3},$

which, upon regrouping terms gives,

$p$

$=$

$\frac{1}{5}\left(\frac{3}{\pi }{)}^{2/3}\right(\frac{1}{2^4{q}_e^2}{)}^{1/3}\frac{h^2}{m_e}(\frac{\rho }{2m_H}{)}^{5/3}.$

Recognizing that Milne set $q_e=2$, as "the statistical weight of an electron," and that he adopted a molecular weight of the electrons, ${\mu }_{e^{-}}=2$, this expression for the equation of state exactly matches our expression for $P_{\mathrm{d}\mathrm{e}\mathrm{g}}{|}_{\mathrm{N}\mathrm{R}}$. Our enlistment of an $n_c=\frac{3}{2}$ polytropic equation of state for the core is therefore also perfectly aligned with Milne's treatment of the core; in particular, according to Milne, at each radial location throughout the core the total pressure can be obtained from the expression,

$P=\frac{K}{\beta }{\rho }^{5/3},$

with Milne's coefficient, $K$, having the same definition as our coefficient, $K_c$

The Point-Source Model

According to Chapter IX.3 (p. 332) of [C67], in the so-called "point-source" model, "… it is assumed that the entire source of energy is liberated at the center of the star; analytically, the assumption is that $L_r=\mathrm{c}\mathrm{o}\mathrm{n}\mathrm{s}\mathrm{t}\mathrm{a}\mathrm{n}\mathrm{t}=L$."

Handling Radiation Transport

Here we begin with the familiar expression for the radiation flux,

${\overrightarrow{F}}_{\mathrm{r}\mathrm{a}\mathrm{d}}$	$=$	$-\frac{c}{3\rho {\kappa }_R}\mathrm{\nabla }(a_{\mathrm{r}\mathrm{a}\mathrm{d}}{T}^4)$	$=$	$-{\chi }_{\mathrm{r}\mathrm{a}\mathrm{d}}\mathrm{\nabla }T,$
[Shu92], Vol. I, §2, p. 17, Eq. (2.17)			and    [T78], §3.4, p. 57, Eq. (67)

where [T78] refers to

${\chi }_{\mathrm{r}\mathrm{a}\mathrm{d}}$

$\equiv$

$\frac{4c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{T}^3}{3\kappa \rho },$

[T78], §3.4, p. 57, Eq. (68)

as the coefficient of radiative conductivity. When modeling spherically symmetric configurations, the radiation flux has only a radial component, that is, ${\overrightarrow{F}}_{\mathrm{r}\mathrm{a}\mathrm{d}}={\hat{e}}_r(F_r)$. And, as pointed out in the context of Eq. (170) on p. 214 of [C67] … the quantity $L_r\equiv 4\pi r^2{F}_r$, which is the net amount of energy crossing a spherical surface of radius $r$, is generally introduced instead of $F_r$. We therefore have,

$\frac{L_r}{4\pi r^2}$	$=$	$-\frac{c}{3\rho {\kappa }_R}\frac{d}{dr}(a_{\mathrm{r}\mathrm{a}\mathrm{d}}{T}^4)$
$\Rightarrow \frac{dT}{dr}$	$=$	$-\frac{3}{4c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\frac{\rho {\kappa }_R}{T^3}\frac{L_r}{4\pi r^2}$

[C67], Chapter V, Eq. (171)
[Clayton68], §6, Eq. (6-4a)
[KW94], §9.1, Eq. (9.6)
[HK94], §7.1, Eq. (7.8)
[BLRY07], §5.2, Eq. (5.15)

Dimensional Analysis: $\frac{{\kappa }_{R}L}{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}$ $\sim$ $\frac{r{T}^4}{\rho }\sim m^{-1}{\ell }^4({}^{\circ }K{)}^4.$ NOTE: This is consistent with the opacity, ${\kappa }_R\sim ({\ell }^2{m}^{-1})$.

Harrison's Approach

Following M. Hall Harrison (1946, ApJ, Vol. 103, 193), we seek to solve this last expression in concert with solutions to a pair of additional key governing relations for spherically symmetric equilibrium configurations, namely,

$\frac{dP}{dr}=-\frac{G{M}_r\rho }{r^2}$	;	$\frac{d{M}_r}{dr}=4\pi r^2\rho$
M. Hall Harrison (1946), p. 196, Eq. (20)

while adopting (see related discussion)

Form A
of the Ideal Gas Equation of State,

$P_{\mathrm{g}\mathrm{a}\mathrm{s}}=\frac{\mathrm{\Re }}{\overline{\mu }}\rho T$

and adopting Kramers' opacity law, that is,

${\kappa }_R\to {\kappa }_{\mathrm{K}\mathrm{r}\mathrm{a}\mathrm{m}\mathrm{e}\mathrm{r}\mathrm{s}}$

$=$

${\kappa }_0\rho T^{-7/2}.$

Dimensional Analysis: $\left[\frac{{\kappa }_{0}L}{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]$ $\sim$ $\frac{r{T}^{15/2}}{{\rho }^2}\sim m^{-2}{\ell }^7({}^{\circ }K{)}^{15/2}$ $\frac{\mathfrak{\Re }}{\mu }$ $\sim$ $t^{-2}{\ell }^2({}^{\circ }K{)}^{-1}$ We note as well that the leading coefficient in Kramers' opacity is, ${\kappa }_0$ $\approx$ $5\times 10^{22}{\mathrm{c}\mathrm{m}}^5{\mathrm{g}}^{-2}({}^{\circ }K{)}^{7/2}.$ [Clayton68], §3.3, Eq. (3-170) [KW94], §17.2, Eq. (17.5) [HK94], §4.4.2, Eq. (4.35)

Does a Polytropic Relation Work?

Let's examine whether a point-source model can be represented by a polytropic relation.

Adopting Temperature (instead of enthalpy)

$P$	$=$	$K{\rho }^{1+1/n}\Rightarrow \rho =(\frac{P}{K}{)}^{n/(n+1)};$
$\left(\frac{\mathfrak{\Re }}{\mu }\right)\rho T$	$=$	$K{\rho }^{1+1/n}\Rightarrow T=\left(\frac{K}{\mathfrak{\Re }/\mu }\right){\rho }^{1/n};$
$T^n$	$=$	$(\frac{K}{\mathfrak{\Re }/\mu }{)}^n\rho \Rightarrow T^n=(\frac{K}{\mathfrak{\Re }/\mu }{)}^n(\frac{P}{K}{)}^{n/(n+1)}\Rightarrow T^{(n+1)}=(\frac{K}{\mathfrak{\Re }/\mu }{)}^{(n+1)}\left(\frac{P}{K}\right).$

Hydrostatic balance is governed by the single 2^nd order ODE,

$\frac{1}{r^2}\frac{d}{dr}\left[\frac{r^2}{\rho }\frac{dP}{dr}\right]$

$=$

$-4\pi G\rho .$

Normally in order to arrive at the Lane-Emden equation, $P$ is converted to $\rho$; here, let's convert both $P$ and $\rho$ to $T$. First, on the RHS we have,

$\rho$

$=$

$(\frac{\mathfrak{\Re }/\mu }{K}{)}^n{T}^n;$

and second, on the LHS we have,

$\frac{1}{\rho }\frac{dP}{dr}$	$=$	$(\frac{K}{\mathfrak{\Re }/\mu }{)}^n{T}^{-n}\cdot \frac{d}{dr}[K^{-n}(\mathfrak{\Re }/\mu {)}^{(n+1)}{T}^{(n+1)}]$
	$=$	$\left(\frac{\mathfrak{\Re }}{\mu }\right)T^{-n}\cdot \frac{d}{dr}\left[T^{(n+1)}\right]$
	$=$	$(n+1)\left(\frac{\mathfrak{\Re }}{\mu }\right)\frac{dT}{dr}$
	$=$	$(n+1)\left(\frac{\mathfrak{\Re }}{\mu }\right)\{-\frac{3}{4c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\frac{\rho {\kappa }_R}{T^3}\frac{L}{4\pi r^2}\}$
	$=$	$-(n+1)\left(\frac{\mathfrak{\Re }}{\mu }\right)\left[\frac{3L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]\left[\frac{\rho }{r^2{T}^3}\right]{\kappa }_0\rho T^{-7/2}$
$\Rightarrow \frac{r^2}{\rho }\frac{dP}{dr}$	$=$	$-(n+1)\left(\frac{\mathfrak{\Re }}{\mu }\right)\left[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]{\rho }^2{T}^{-13/2}$
	$=$	$-(n+1)K^{-2n}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{2n+1}\right[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}]T^{(4n-13)/2}.$

So, the hydrostatic-balance condition becomes,

$-(n+1)K^{-2n}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{2n+1}\right[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}]\cdot \frac{1}{r^2}\frac{d{T}^{(4n-13)/2}}{dr}$	$=$	$-4\pi G(\frac{\mathfrak{\Re }/\mu }{K}{)}^n{T}^n$
$\Rightarrow \frac{(n+1)}{4\pi G{K}^{2n}}\left(\frac{\mathfrak{\Re }/\mu }{K}{)}^{-n}\right(\frac{\mathfrak{\Re }}{\mu }{)}^{2n+1}\left[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]\cdot \frac{1}{r^2}\frac{d{T}^{(4n-13)/2}}{dr}$	$=$	$T^n$
$\Rightarrow \frac{{𝒜}}{r^2}\frac{d{T}^{(4n-13)/2}}{dr}$	$=$	$T^n$
$\Rightarrow {{𝒜}}^{-1}{r}^{2}dr$	$=$	$T^{-n}\cdot d{T}^{(4n-13)/2},$

where,

${𝒜}$

$\equiv$

$\frac{(n+1)}{4\pi G{K}^n}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{n+1}\right[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}].$

Dimensional Analysis: $\left[\frac{{\kappa }_{0}L}{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right]$ $\sim$ $m^{-2}{\ell }^7({}^{\circ }K{)}^{15/2}$ $\frac{\mathfrak{\Re }}{\mu }$ $\sim$ $t^{-2}{\ell }^2({}^{\circ }K{)}^{-1}$ polytropic $K$ $\sim$ $t^{-2}{\ell }^{2+3/n}{m}^{-1/n}$ Hence, ${𝒜}$ $\sim$ $G^{-1}{K}^{-n}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{n+1}\right[m^{-2}{\ell }^7({}^{\circ }K{)}^{15/2}]$   $\sim$ $\left[{\ell }^{-3}m{t}^2\right]\left[t^{-2}{\ell }^{2+3/n}{m}^{-1/n}{]}^{-n}\right[t^{-2}{\ell }^2({}^{\circ }K{)}^{-1}{]}^{n+1}[m^{-2}{\ell }^7({}^{\circ }K{)}^{15/2}]$   $\sim$ $\left[{\ell }^{-3}\right]\left[{\ell }^{2+3/n}{]}^{-n}\right[{\ell }^2{]}^{n+1}\left[{\ell }^7\right]({}^{\circ }K{)}^{13/2-n}\sim {\ell }^3({}^{\circ }K{)}^{13/2-n}.$ Now, the characteristic length scale for polytropic configurations is given by the expression, $a_{\mathrm{n}}^2\equiv [\frac{(n+1)K}{4\pi G}\cdot {\rho }_c^{(1-n)/n}].$ If we divide ${𝒜}$ by $a_n^3$, the resulting expression should give us the characteristic temperature of the envelope. Specifically, we find that, $\frac{{𝒜}}{a_n^3}$ $=$ $\frac{(n+1)}{4\pi G{K}^n}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{n+1}\right[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}]\times [\frac{(n+1)K_n}{4\pi G}\cdot {\rho }_c^{(1-n)/n}{]}^{-3/2}$   $=$ $(n+1{)}^{-1/2}{\rho }_c^{3(n-1)/2n}(\frac{\mathfrak{\Re }}{\mu }{)}^{n+1}\left[\frac{3{\kappa }_{0}L}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}\right](4\pi G{)}^{1/2}{K}^{-n-3/2}$   $\sim$ $\left[m{\ell }^{-3}{]}^{3(n-1)/2n}\right[t^{-2}{\ell }^2({}^{\circ }K{)}^{-1}{]}^{n+1}[m^{-2}{\ell }^7({}^{\circ }K{)}^{15/2}]\left[{\ell }^3{m}^{-1}{t}^{-2}{]}^{1/2}\right[t^{-2}{\ell }^{2+3/n}{m}^{-1/n}{]}^{-n-3/2}$   $\sim$ $t^{-2n-2-1+2n+3}{m}^{3(n-1)/2n-2-1/2+1+3/2n}{\ell }^{-9(n-1)/2n+2n+2+7+3/2}[{\ell }^{(2n+3)/n}{]}^{-(2n+3)/2}({}^{\circ }K{)}^{13/2-n}$   $\sim$ ${\ell }^{(9+4n^2+12n)/2n}{\ell }^{-(2n+3{)}^2/2n}({}^{\circ }K{)}^{13/2-n}$   $\sim$ $({}^{\circ }K{)}^{(13-2n)/2}.$

Quite generally we can write,

$\frac{1}{\alpha }\frac{d{T}^{\alpha }}{dr}$

$=$

$T^{\alpha -1}\frac{dT}{dr}.$

Rewriting the hydrostatic-balance condition, we find that,

${{𝒜}}^{-1}{r}^2$

$=$

$T^{-n}\cdot \frac{d}{dr}\left[T^{(4n-13)/2}\right]=T^{-n}\left(\frac{4n-13}{2}\right)T^{(4n-15)/2}\cdot \frac{dT}{dr}=\left(\frac{4n-13}{2}\right)T^{(2n-15)/2}\cdot \frac{dT}{dr}.$

Associating the exponents,

$\alpha -1$

$=$

$\frac{2n-15}{2}\Rightarrow \alpha =\frac{2n-13}{2},$

we can write,

${{𝒜}}^{-1}{r}^2$	$=$	$\left(\frac{4n-13}{2}\right)\left(\frac{2}{2n-13}\right)\frac{d}{dr}\left[T^{(2n-13)/2}\right]$
$\Rightarrow 3d(r^3)$	$=$	${𝒜}\left(\frac{4n-13}{2n-13}\right)d\left[T^{(2n-13)/2}\right]$
$\Rightarrow 0$	$=$	$d\left[{𝒜}\right(\frac{13-4n}{13-2n})T^{(2n-13)/2}-3r^3]$
$\Rightarrow$ constant	$=$	$\frac{{𝒜}}{a_n^3}\left(\frac{13-4n}{13-2n}\right)T^{(2n-13)/2}-3(\frac{r}{a_n}{)}^3.$

Adopting Enthalpy (instead of Temperature)

For polytropic configurations the enthalpy, $H$, can easily be adopted in place of temperature via the relation,

$\left(\frac{\mathfrak{\Re }}{\mu }\right)T$

$=$

$\frac{H}{(n+1)}.$

Hence,

$P$

$=$

$K{\rho }^{1+1/n};$

$H$

$=$

$K{\rho }^{1/n};$

$H^{n+1}$

$=$

$K^{n}P.$

And the radiation-transport equation can be rewritten in the form,

$\frac{L_r}{4\pi r^2}$	$=$	$-\frac{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}{3\rho {\kappa }_R(n+1{)}^4}(\frac{\mathfrak{\Re }}{\mu }{)}^{-4}\frac{d{H}^4}{dr}$
	$=$	$-\frac{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}{3{\kappa }_0(n+1{)}^4}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{-4}\right[{\rho }^{-2}{T}^{7/2}]\frac{d{H}^4}{dr}$
	$=$	$-\frac{c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}}{3{\kappa }_0(n+1{)}^4}\left(\frac{\mathfrak{\Re }}{\mu }{)}^{-4}\right\{\left(\frac{K}{H}{)}^{2n}\right[\left(\frac{\mathfrak{\Re }}{\mu }{)}^{-1}\frac{H}{(n+1)}{]}^{7/2}\right\}4H^3\frac{dH}{dr}$
	$=$	$-\frac{4c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{K}^{2n}}{3{\kappa }_0(n+1{)}^{15/2}}(\frac{\mathfrak{\Re }}{\mu }{)}^{-15/2}{H}^{(13-4n)/2}\frac{dH}{dr}$
$\Rightarrow r^2\frac{dH}{dr}$	$=$	$-\left[\frac{3{\kappa }_{0}L(n+1{)}^{15/2}}{16\pi c{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{K}^{2n}}\right(\frac{\mathfrak{\Re }}{\mu }{)}^{15/2}]H^{(4n-13)/2}.$

In terms of the enthalpy, the hydrostatic-balance expression becomes,

$-4\pi G\left[\frac{H^n}{K^n}\right]$	$=$	$\frac{1}{r^2}\frac{d}{dr}\left\{r^2\right[\frac{K^n}{H^n}\left]\frac{d}{dr}\right[K^{-n}{H}^{n+1}\left]\right\}$
$\Rightarrow -4\pi G{H}^n$	$=$	$\frac{K^n}{r^2}\frac{d}{dr}\left\{\right[\frac{r^2}{H^n}\left]\frac{d}{dr}\right[H^{n+1}\left]\right\}$
	$=$	$\frac{(n+1)K^n}{r^2}\frac{d}{dr}\left\{r^2\frac{dH}{dr}\right\}.$

Combining these two equations gives,

$r^2{H}^n$	$=$	${ℬ}\cdot \frac{d}{dr}\left\{H^{(4n-13)/2}\right\}$
	$=$	$\frac{(4n-13){ℬ}}{2}\cdot H^{(4n-15)/2}\frac{dH}{dr}$
$\Rightarrow \left[\frac{2}{(4n-13){ℬ}}\right]r^2$	$=$	$H^{(2n-15)/2}\frac{dH}{dr}$

where,

${ℬ}$

$\equiv$

$\left[\frac{3{\kappa }_{0}L(n+1{)}^{17/2}}{64{\pi }^{2}Gc{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}{K}^n}\right(\frac{\mathfrak{\Re }}{\mu }{)}^{15/2}].$

As above, quite generally we can write,

$\frac{1}{\alpha }\frac{d{H}^{\alpha }}{dr}$

$=$

$H^{\alpha -1}\frac{dH}{dr}.$

So, associating the exponents, we appreciate that,

$\alpha -1$

$=$

$\frac{2n-15}{2}\Rightarrow \alpha =\frac{2n-13}{2}.$

Hence, we have,

$\left[\frac{2}{(4n-13){ℬ}}\right]r^2$	$=$	$\frac{2}{(2n-13)}\frac{d}{dr}\left[H^{(2n-13)/2}\right]$
$\Rightarrow r^2$	$=$	$\frac{(4n-13){ℬ}}{(2n-13)}\frac{d}{dr}\left[H^{(2n-13)/2}\right]$
$\Rightarrow d\left[\frac{r^3}{a_n^3}\right]$	$=$	$\frac{3(4n-13){ℬ}}{(2n-13)a_n^3}\cdot d\left[H^{(2n-13)/2}\right]$
$\Rightarrow d\left[{\xi }^3\right]$	$=$	$\left[\frac{3(4n-13)}{(2n-13)}\right][\frac{{ℬ}}{a_n^3}\cdot H_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}^{(2n-13)/2}]d[\frac{H}{H_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}}{]}^{(2n-13)/2};$

so, if we adopt the definition,

$H_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}$

$\equiv$

$[\frac{(2n-13)}{3(4n-13)}\cdot \frac{a_n^3}{{ℬ}}{]}^{2/(2n-13)},$

the relation becomes,

$d\left[{\xi }^3\right]$

$=$

$d[\frac{H}{H_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}}{]}^{(2n-13)/2}.$

Power-Law Density Distribution

In an accompanying discussion, we have demonstrated that power-law density distributions can provide analytic solutions of the Lane-Emden equation, although the associated boundary conditions do not naturally conform to the boundary conditions that are suitable to astrophysical configurations. We have just shown that the point-source envelope configuration appears to admit a power-law temperature solution; specifically, setting the integration constant to zero, our result gives,

$\frac{{𝒜}}{a_n^3}\left(\frac{13-4n}{13-2n}\right)[\frac{T}{T_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}}{]}^{(2n-13)/2}$

$=$

$3{\xi }^3,$

where,

$\xi$

$\equiv$

$\frac{r}{a_n},$

and,

$T_{\mathrm{n}\mathrm{o}\mathrm{r}\mathrm{m}}$

$\equiv$

$[\frac{{𝒜}}{a_n^3}{]}^{2/(13-2n)}.$

Our Derivation

Steps 2 & 3

Throughout the core, the properties of this bipolytrope can be expressed in terms of the Lane-Emden function, $\theta (\xi )$, which derives from a solution of the 2^nd-order ODE,

$\frac{1}{{\xi }^2}\frac{d}{d\xi }\left[{\xi }^2\frac{d\theta }{d\xi }\right]=-{\theta }^{3/2},$

subject to the boundary conditions,

$\theta =1$       and       $\frac{d\theta }{d\xi }=0$       at       $\xi =0$.

The first zero of the function $\theta (\xi )$ and, hence, the surface of the corresponding isolated $n=\frac{3}{2}$ polytrope is located at ${\xi }_s=3.65375$ (see Table 4 in chapter IV on p. 96 of [C67]). Hence, the interface between the core and the envelope can be positioned anywhere within the range, $0<{\xi }_i<{\xi }_s=3.65375$.

Step 4: Throughout the core (0 ≤ ξ ≤ ξ_i)

Specify: $K_c$ and ${\rho }_0\Rightarrow$
$\rho$	$=$	${\rho }_0{\theta }^{n_c}$	$=$	${\rho }_0{\theta }^{3/2}$
$P$	$=$	$K_c{\rho }_0^{1+1/n_c}{\theta }^{n_c+1}$	$=$	$K_c{\rho }_0^{5/3}{\theta }^{5/2}$
$r$	$=$	$[\frac{(n_c+1)K_c}{4\pi G}{]}^{1/2}{\rho }_0^{(1-n_c)/(2n_c)}\xi$	$=$	$[\frac{5K_c}{8\pi G}{]}^{1/2}{\rho }_0^{-1/6}\xi$
$M_r$	$=$	$4\pi \left[\frac{(n_c+1)K_c}{4\pi G}{]}^{3/2}{\rho }_0^{(3-n_c)/(2n_c)}\right(-{\xi }^2\frac{d\theta }{d\xi })$	$=$	$\frac{1}{2^2(2\pi {)}^{1/2}}\left[\frac{5K_c}{G}{]}^{3/2}{\rho }_0^{1/2}\right(-{\xi }^2\frac{d\theta }{d\xi })$

By comparison, the expressions that Milne (1930) derived for the run of $\rho$, $r$, and $M_r$ throughout the core are presented in his paper as, respectively, equations (90), (88), and (87). In an effort to facilitate this comparison, Milne's expressions — which also specifically apply to the outer edge of the core, whose identity is associated with primed variable names in Milne's notation — are reprinted as extracted images in the following boxed-in table.

Equations extracted† from E. A. Milne (1930) "The Analysis of Stellar Structure" MNRAS, vol. 91, pp. 4 - 55 © Royal Astronomical Society
Milne (1930) Milne (1930)
†Equations displayed here, as a single digital image, with presentation order & layout modified from the original publication.

It is clear that the agreement between our derivation and Milne's is exact, once it is realized that Milne has used $\psi (\eta )$ to represent the Lane_Emden function for the $n_c=\frac{3}{2}$ core, whereas we have represented this function by $\theta (\xi )$; and Milne has identified the configuration's central density as ${\lambda }_2$, whereas we have used the notation, ${\rho }_0$.

Step 5: Interface Conditions

			Setting $n_c=\frac{3}{2}$, $n_e=3$, and ${\varphi }_i=1\Rightarrow$
$\frac{{\rho }_e}{{\rho }_0}$	$=$	$\left(\frac{{\mu }_e}{{\mu }_c}\right){\theta }_i^{n_c}{\varphi }_i^{-n_e}$	$=$	$\left(\frac{{\mu }_e}{{\mu }_c}\right){\theta }_i^{3/2}$
$\left(\frac{K_e}{K_c}\right)$	$=$	${\rho }_0^{1/n_c-1/n_e}(\frac{{\mu }_e}{{\mu }_c}{)}^{-(1+1/n_e)}{\theta }_i^{1-n_c/n_e}$	$=$	${\rho }_0^{1/3}(\frac{{\mu }_e}{{\mu }_c}{)}^{-4/3}{\theta }_i^{1/2}$
$\frac{{\eta }_i}{{\xi }_i}$	$=$	$\left[\frac{n_c+1}{n_e+1}{]}^{1/2}\right(\frac{{\mu }_e}{{\mu }_c}){\theta }_i^{(n_c-1)/2}{\varphi }_i^{(1-n_e)/2}$	$=$	$\left(\frac{5}{8}{)}^{1/2}\right(\frac{{\mu }_e}{{\mu }_c}){\theta }_i^{1/4}$
$(\frac{d\varphi }{d\eta }{)}_i$	$=$	$\left[\frac{n_c+1}{n_e+1}{]}^{1/2}{\theta }_i^{-(n_c+1)/2}{\varphi }_i^{(n_e+1)/2}\right(\frac{d\theta }{d\xi }{)}_i$	$=$	$\left(\frac{5}{8}{)}^{1/2}{\theta }_i^{-5/4}\right(\frac{d\theta }{d\xi }{)}_i$

Step 8: Throughout the envelope (η_i ≤ η ≤ ξ_s)

					Knowing: $K_e/K_c$ and ${\rho }_e/{\rho }_0$ from Step 5   $\Rightarrow$
$\rho$	$=$	${\rho }_e{\varphi }^{n_e}$	$=$	${\rho }_0\left(\frac{{\rho }_e}{{\rho }_0}\right){\varphi }^3$	$=$	${\rho }_0\left(\frac{{\mu }_e}{{\mu }_c}\right){\theta }_i^{3/2}{\varphi }^3$
$P$	$=$	$K_e{\rho }_e^{1+1/n_e}{\varphi }^{n_e+1}$	$=$	$K_c{\rho }_0^{4/3}\left(\frac{K_e}{K_c}\right)(\frac{{\rho }_e}{{\rho }_0}{)}^{4/3}{\varphi }^4$	$=$	$K_c{\rho }_0^{5/3}{\theta }_i^{5/2}{\varphi }^4$
$r$	$=$	$[\frac{(n_e+1)K_e}{4\pi G}{]}^{1/2}{\rho }_e^{(1-n_e)/(2n_e)}\eta$	$=$	$\left[\frac{K_c}{\pi G}{]}^{1/2}{\rho }_0^{-1/3}\right(\frac{K_e}{K_c}{)}^{1/2}(\frac{{\rho }_e}{{\rho }_0}{)}^{-1/3}\eta$	$=$	$\left[\frac{K_c}{\pi G}{]}^{1/2}{\rho }_0^{-1/6}\right(\frac{{\mu }_e}{{\mu }_c}{)}^{-1}{\theta }_i^{-1/4}\eta$
$M_r$	$=$	$4\pi \left[\frac{(n_e+1)K_e}{4\pi G}{]}^{3/2}{\rho }_e^{(3-n_e)/(2n_e)}\right(-{\eta }^2\frac{d\varphi }{d\eta })$	$=$	$4\pi \left[\frac{K_c}{\pi G}{]}^{3/2}\right(\frac{K_e}{K_c}{)}^{3/2}(-{\eta }^2\frac{d\varphi }{d\eta })$	$=$	$\left(\frac{2^4}{\pi }{)}^{1/2}\right[\frac{K_c}{G}{]}^{3/2}{\rho }_0^{1/2}\left(\frac{{\mu }_e}{{\mu }_c}{)}^{-2}{\theta }_i^{3/4}\right(-{\eta }^2\frac{d\varphi }{d\eta })$

Instead of working completely across this table in order to relate the envelope's density, radial coordinate, and mass to properties of the core, it is worth pausing to insert into the leftmost set of relations the expressions for ${\rho }_e$ and $K_e$ that were derived above. In doing this, we obtain,

$\rho$	$=$	${\rho }_e{\varphi }^3$	$=$	$\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^{-1}\frac{\beta }{(1-\beta )}\cdot \frac{1}{3}{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}]{\lambda }^3{\varphi }^3,$
$r$	$=$	$[\frac{K_e}{\pi G}{]}^{1/2}{\rho }_e^{-1/3}\eta$	$=$	$\frac{1}{(\pi G{)}^{1/2}}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/6}\left\{{\lambda }^3\right[(\frac{\mathrm{\Re }}{{\mu }_e}{)}^{-1}\frac{\beta }{(1-\beta )}\cdot \frac{1}{3}{a}_{\mathrm{r}\mathrm{a}\mathrm{d}}]{\}}^{-1/3}\eta$
			$=$	$\frac{1}{(\pi G{)}^{1/2}}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/6}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^2\frac{(1-\beta {)}^2}{{\beta }^2}(\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{)}^2{]}^{1/6}\frac{\eta }{\lambda }$
			$=$	$\left(\frac{3}{\pi a_{\mathrm{r}\mathrm{a}\mathrm{d}}G}{)}^{1/2}\right(\frac{\mathrm{\Re }}{{\mu }_e})\frac{(1-\beta {)}^{1/2}}{\beta }\cdot \frac{\eta }{\lambda },$
$M_r$	$=$	$4\pi \left[\frac{K_e}{\pi G}{]}^{3/2}\right(-{\eta }^2\frac{d\varphi }{d\eta })$	$=$	$\frac{4\pi }{(\pi G{)}^{3/2}}\left[\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^4\left(\frac{1-\beta }{{\beta }^4}\right)\frac{3}{a_{\mathrm{r}\mathrm{a}\mathrm{d}}}{]}^{1/2}(-{\eta }^2\frac{d\varphi }{d\eta })$
			$=$	$4\left(\frac{3}{\pi a_{\mathrm{r}\mathrm{a}\mathrm{d}}{G}^3}{)}^{1/2}\right(\frac{\mathrm{\Re }}{{\mu }_e}{)}^2\frac{(1-\beta {)}^{1/2}}{{\beta }^2}(-{\eta }^2\frac{d\varphi }{d\eta }).$

By comparison, the expressions that 📚 Milne (1930) derived for the run of $\rho$, $r$, and $M_r$ throughout the envelope are presented in his paper as, respectively, equations (89), (86), and (85). In an effort to facilitate this comparison, Milne's expressions — which also specifically apply to the base of the envelope, whose identity is associated with primed variable names in Milne's notation — are reprinted as extracted images in the following boxed-in table.

Equations extracted† from E. A. Milne (1930) The Analysis of Stellar Structure Monthly Notices of the Royal Astronomical Society, Vol. 91, pp. 4 - 55
Milne (1930) Milne (1930)
†Equations displayed here, as a single digital image, with presentation order & layout modified from the original publication.

The agreement between our derivation and Milne's is exact, once it is realized that Milne has used $\theta (\xi )$ to represent the Lane_Emden function for the $n_e=3$ envelope, whereas we have represented this function by $\varphi (\eta )$; and in place of Milne's coefficient, ${\lambda }_1$, we have simply written, $\lambda$.

See Also

• M. Hall Harrison (1944, ApJ, 100, 343 - 346), The Generalized Cowling Model — Bibliographic Code: 1944ApJ...100..343H
  (3^rd paragraph on p. 343): "We shall consider a composite model made up of a central core described by the Lane-Emden function of index $n=\frac{3}{2}$ and a point-source envelope."
• M. Hall Harrison (1946, ApJ, 103, 193 - 206), Stellar Models with Partially Degenerate Isothermal Cores and Point-Source Envelopes — Bibliographic Code: 1946ApJ...103..193H
• M. Hall Harrison (1947, ApJ, 105, 322 - 326), Stellar Models with Isothermal Cores and Point-Source Envelopes — Bibliographic Code: 1947ApJ...105..322H
• K. Suda & Z. Hitotuyanagi (1960, PASJapan, 12, 21 - 27), Stellar Models with Partially Degenerate Isothermal Cores