Template:Math/EQ EllipticIntegral02

	$\frac{2E(k)}{\pi }$	$=$	$1-\frac{1}{2^2}{k}^2-\frac{1^2\cdot 3}{2^2\cdot 4^2}{k}^4-(\frac{1\cdot 3\cdot 5}{2^4\cdot 3}{)}^2\frac{k^6}{5}-(\frac{1\cdot 3\cdot 5\cdot 7}{2^7\cdot 3}{)}^2\frac{k^8}{7}-\cdots -[\frac{(2n-1)!!}{2^{n}n!}{]}^2\frac{k^{2n}}{2n-1}-\cdots$
Gradshteyn & Ryzhik (1965), §8.114.1