Appendix/Mathematics/Hypergeometric: Difference between revisions

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If we furthermore make the substitution,
If we furthermore adopt the variable definition,
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we obtain equation (1) of [https://ui.adsabs.harvard.edu/abs/1970PASA....1..325V/abstract R. Van der Borght (1970)]
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  <td align="right">
<math>\mu</math>
  </td>
  <td align="center">
<math>\equiv</math>
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  <td align="left">
<math>\biggl(\frac{g_0 \rho_0 r_0}{P_0}\biggr) \, ,</math>
  </td>
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we obtain equation (1) of [https://ui.adsabs.harvard.edu/abs/1970PASA....1..325V/abstract R. Van der Borght (1970)], namely,
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<math>0</math>
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<math>=</math>
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<math>
\frac{d^2\xi}{dx^2} + \frac{(4-\mu)}{x} \cdot \frac{d\xi}{dx}
+ \biggl[\biggl(\frac{\omega^2\rho_0 R^2}{\gamma_\mathrm{g} P_0} \biggr)
- \frac{\alpha \mu}{x^2} \biggr]\xi \, .
</math>
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=See Also=
=See Also=

Revision as of 12:46, 26 October 2022


Hypergeometric Differential Equation

According to §9.151 (p. 1045) of Gradshteyn & Ryzhik (1965), "… a hypergeometric series is one of the solutions of the differential equation,

0

=

z(1z)d2udz2+[γ(α+β+1)z]dudzαβu,

which is called the hypergeometric equation. And, according to §9.10 (p. 1039) of Gradshteyn & Ryzhik (1965), "A hypergeometric series is a series of the form,

F(α,β;γ;z)

=

1+[αβγ1]z+[α(α+1)β(β+1)γ(γ+1)12]z2+[α(α+1)(α+2)β(β+1)(β+2)γ(γ+1)(γ+2)123]z3+

Among other attributes, Gradshteyn & Ryzhik (1965) note that this, "… series terminates if α or β is equal to a negative integer or to zero."

LAWE

Drawing from an accompanying discussion, we have the,

LAWE:   Linear Adiabatic Wave (or Radial Pulsation) Equation

d2xdr02+[4r0(g0ρ0P0)]dxdr0+(ρ0γgP0)[ω2+(43γg)g0r0]x=0

where,

g0

=

1ρ0dP0dr0.

Multiplying through by R2, and making the variable substitutions,

x

ξ,

r0R

x,

(43γg)

αγg,

the LAWE may be rewritten as,

0

=

d2ξdx2+[4x(g0ρ0RP0)]dξdx+(ρ0R2γgP0)[ω2αγgg0Rx]ξ

 

=

d2ξdx2+1x[4(g0ρ0r0P0)]dξdx+[(ω2ρ0R2γgP0)αx2(g0ρ0r0P0)]ξ.

If we furthermore adopt the variable definition,

μ

(g0ρ0r0P0),

we obtain equation (1) of R. Van der Borght (1970), namely,

0

=

d2ξdx2+(4μ)xdξdx+[(ω2ρ0R2γgP0)αμx2]ξ.

See Also


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